NEET PhysicsUpdated 19 Oct 2026

Magnetism and Matter: NEET PYQs and weightage

Magnetism and Matter carries 1.7 of 100 Physics marks in NEET by past-paper share: 13 of the 758 tagged NEET Physics PYQs in the ViJEEta bank (NEET 2013–2026). It ranks 27 of 30 Physics chapters.

Take the 25-question Magnetism and Matter test Formula sheet ↓All NEET Physics chapters

1.7/100 Weight in Physics

Exam importance (2/5, by past-paper share)

13 NEET PYQs

168 Practice questions

148 With measured difficulty

How the weight is computed: this chapter's tagged NEET PYQs divided by all tagged NEET Physics PYQs in the bank (13 of 758), times 100, with repeated questions counted once. The bank does not store the year of each NEET question, so none is printed. Computed from the bank at build time. Updated 19 Oct 2026.

Magnetism and Matter: formula sheet for NEET

14 formulas, each with when to use it. Copy it onto one page of your notebook: that page is this chapter's handbook.

Torque on a magnet in a field
$τ = m \times B$
$τ = m B sin θ$
Use it when: a magnet or needle sits at angle $θ$ to a uniform field ( $θ$ is between $m$ and $B$ )
Potential energy of a dipole
$U = - m \cdot B = - m B cos θ$
Use it when: finding stable ( $θ = 0^{\circ}$ , $U = - m B$ ) or unstable ( $θ = 18 0^{\circ}$ , $U = + m B$ ) positions; $U = 0$ at $θ = 9 0^{\circ}$
Work to rotate a magnet
$W = U_{final} - U_{initial} = m B (cos θ_{1} - cos θ_{2})$
Use it when: an external torque turns the magnet slowly from $θ_{1}$ to $θ_{2}$ (aligned $\to$ opposite gives $2 m B$ )
Net force in a uniform field
$F_{net} = 0$
Use it when: asked about force (not torque) on a magnet in a uniform field; a non-uniform field gives a force
Axial field of a short magnet
$B_{A} = \frac{μ _{0}}{4 π} \frac{2 m}{r ^{3}}$
Use it when: the point is on the magnet's axis and $r ≫ l$ ; the field points along $m$ ( $μ_{0} /4 π = 1 0^{- 7} T m A^{- 1}$ )
Equatorial field of a short magnet
$B_{E} = - \frac{μ _{0}}{4 π} \frac{m}{r ^{3}}$
Use it when: the point is on the normal bisector and $r ≫ l$ ; the minus sign means opposite to $m$
Gauss's law for magnetism
$\sum B \cdot Δ S = 0 (over any closed surface)$
Use it when: checking whether a field-line picture can be magnetic (no monopoles, lines form closed loops)
Magnetisation
$M = \frac{m _{net}}{V} (unit A m^{- 1})$
Use it when: given the total magnetic moment of a sample and its volume
Field inside a long solenoid
$B_{0} = μ_{0} n I$
$H = n I$
Use it when: a solenoid has $n$ turns per metre; $H$ depends only on the current, not on the core
Total field in a material
$B = μ_{0} (H + M)$
Use it when: you need $B$ , $H$ or $M$ and know the other two
Susceptibility
$M = χH (χ has no unit)$
Use it when: converting the applied $H$ into the magnetisation of a linear material
Permeability links
$μ_{r} = 1 + χ$
$μ = μ_{0} μ_{r} = μ_{0} (1 + χ)$
Use it when: you are given any one of $χ$ , $μ_{r}$ or $μ$ and need the other two
Field with a core
$B = μ H = μ_{0} μ_{r} H$
Use it when: a solenoid is filled with a core of known $μ_{r}$
Material classes
$dia: - 1 \leq χ < 0 (0 \leq μ_{r} < 1)$
$para: 0 < χ < ε (1 < μ_{r} < 1 + ε)$
$ferro: χ ≫ 1 (μ_{r} ≫ 1)$
Use it when: classifying a material; a superconductor is a perfect diamagnet with $χ = - 1$ , $μ_{r} = 0$

Trap

At the same distance r, the axial field is twice the equatorial field, and the equatorial field points opposite to m. Students often drop the 2, or put it on the wrong position.

How does NEET ask Magnetism and Matter?

7 real previous-year questions from this chapter, as printed in the paper, each with its worked solution. Answer the first one here with no sign-in.

Q1PhysicsNEET UG PYQMagnetisation and Magnetic Intensity

Try right here · No sign-in

An iron rod of susceptibility 599 is subjected to a magnetising field of 1200 A

m^{- 1} .

The permeability of the material of the rod is

: (μ_{0} = 4 π \times 1 0^{- 7} T m A^{- 1})

Answer key (C) & worked solution

Correct answer: Option C

χ_{m} = 599, μ_{0} = 4 π \times 1 0^{- 7}

H = 1200 A / m, μ = ?

μ = μ_{0} (1 + χ_{m})

= 4 π \times 1 0^{- 7} (1 + 599)

= 4 π \times 1 0^{- 7} \times 600

= 24 π \times 1 0^{- 5}

μ = 2.4 π \times 1 0^{- 4} T m A^{- 1}

Q2PhysicsNEET UG PYQThe Bar Magnet

θ_{1}

and

θ_{2}

be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip

θ

is given by

cot^{2} θ = cot^{2} θ_{1} - cot^{2} θ_{2}

tan^{2} θ = tan^{2} θ_{1} - tan^{2} θ_{2}

cot^{2} θ = cot^{2} θ_{1} + cot^{2} θ_{2}

tan^{2} θ = tan^{2} θ_{1} + tan^{2} θ_{2}

Answer key (C) & worked solution

Correct answer: Option C

Let B

_{H}

and B

_{V}

be the horizontal and vertical components of earth's magnetic field vector B. Since

θ

is the true angle of dip

∴ tan θ = \frac{B _{V}}{B _{H}} or cot θ = \frac{B _{H}}{B _{V}}

...(i)

Suppose planes 1 and 2 are mutually perpendicular plane and respectively make angles

θ an d (9 0^{\circ} - θ)

with the magnetic meridian. The vertical component of earth's magnetic field remain same in the two planes but the effective horizontal components in the planes will be

B_{1} = B_{H} cos θ and B_{2} = B_{H} sin θ

The angles of dip

θ_{1} and θ_{2}

in the two planes are given by

tan θ_{1} = \frac{B _{V}}{B _{1}}

tan θ_{1} = \frac{B _{V}}{B _{H} cos θ}

or cot θ_{1} = \frac{B _{H} cos θ}{B _{V}}

...(ii)

Similarly,

cot θ_{2} = \frac{B _{H} sin θ}{B _{V}}

..(iii)

From eqns. (ii) and (iii)

cot^{2} θ_{1} + cot^{2} θ_{2} = \frac{B _{H} ^{2}}{B _{V} ^{2}}

[from eqn. (i)]

∴ cot^{2} θ_{1} + cot^{2} θ_{2} = cot^{2} θ

Q3PhysicsNEET UG PYQMagnetism and Gauss's Law

The net magnetic flux through any closed surface is :

APositive

BInfinity

CNegative

DZero

Answer key (D) & worked solution

Correct answer: Option D

Magnetic field exist in Closed Loops (Monopoles do not exist) Closed Loops (Monopoles do not exist)

ϕ B . d A = 0

(Gauss law for magnetism)

Q4PhysicsNEET UG PYQMagnetic Properties of Materials

Match List - I with List - II. List – IList – II(a) [Fe(CN)

_{6}

]

^{3 -}

(i) 5.92 B.M.(b) [Fe(H

_{2}

_{6}

]

^{3 +}

(ii) 0 B.M.(c) [Fe(CN)

_{6}

]

^{4 -}

(iii) 4.90 B.M.(d) [Fe(H

_{2}

_{6}

]

^{2 +}

(iv) 1.73 B.M. Choose the correct answer from the options given below.

A(a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

B(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

C(a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)

D(a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)

Answer key (B) & worked solution

Correct answer: Option B

(a) [Fe(CN)

_{6}

]

^{3 -}

: Fe

^{3 +}

= [Ar] 3d

^{5}

. In presence of strong field CN–, electron pairing takes place and the number of unpaired electrons = 1. Thus,

μ = 3 B .M .

(b) [Fe(H

_{2}

_{6}

]

^{3 +}

: Fe

^{3 +}

= [Ar] 3d

^{5}

. In presence of weak field H

_{2}

O, electron pairing does not take place and the number of unpaired electrons = 5. Thus,

μ = 35 B .M .

_{6}

]4–: Fe

^{2 +}

= [Ar] 3d

^{6}

In the presence of strong field CN– ligand, electrons will be paired and

μ = 0 B .M .

(d) [Fe(H

_{2}

_{6}

]

^{2 +}

: Fe

^{2 +}

= [Ar] 3d

^{6}

. In presence of weak field H

_{2}

O, electron pairing does not take place and the number of unpaired electrons = 4. Thus,

μ = 24 B .M .

Q5PhysicsNEET UG PYQThe Bar Magnet

A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equilibrium state. The energy required to rotate it by 60

^{o}

is W. Now the torque required to keep the magnet in this new position is

3 W

\frac{3 W}{2}

\frac{2 W}{3}

\frac{W}{3}

Answer key (A) & worked solution

Correct answer: Option A

τ = M B sin θ

… (1)

W = M B (1 - cos 6 0^{\circ})

… (2)

\frac{τ}{W} = \frac{3 /2}{1/2} \Rightarrow τ = W 3

Q6PhysicsNEET UG PYQMagnetic Properties of Materials

A thin diamagnetic rod is placed vertically between the poles of an electromagnet. When the current in the electromagnet is switched on, then the diamagnetic rod is pushed up, out of the horizontal magnetic field. Hence the rod gains gravitational potential energy. The work required to do this comes from

AThe lattice structure of the material of the rod

BThe magnetic field

CThe current source

DThe induced electric field due to the changing magnetic field

Answer key (C) & worked solution

Correct answer: Option C

Energy of current source will be converted into potential energy of the rod.Also,When current source is switched on, magnetic field sets up between poles on electromagnet. Diamagnetic material, due to its tendency to move from stronger to weaker field, is thus repelled out.

Q7PhysicsNEET UG PYQMagnetisation and Magnetic Intensity

The magnetic susceptibility is negative for

ADiamagnetic material only

BParamagnetic material only

CFerromagnetic material only

DParamagnetic and ferromagnetic materials

Answer key (A) & worked solution

Correct answer: Option A

Magnetic susceptibility =

χ

it is negative for dia-magnetic materials only

Which topics in Magnetism and Matter carry the most questions?

All 4 topics, by tagged PYQs, then practice questions. Counted from the bank. Updated 19 Oct 2026.

Topic	PYQs	Practice questions
The Bar Magnet	7	80
Magnetisation and Magnetic Intensity	3	29
Magnetic Properties of Materials	2	58
Magnetism and Gauss's Law	1	1

Why does Magnetism and Matter show "–" until you answer 3 questions?

Unknown is not zero. Until you answer at least 3 graded questions in Magnetism and Matter, ViJEEta shows – instead of a zero or a 50% default. Book exercises can raise chapter mastery up to 0.60, adaptive practice up to 0.75, and only a timed chapter test or mock can certify 0.80 and above.

How ViJEEta scores you

What happens when you test Magnetism and Matter?

Every chapter test is 25 questions. It starts at moderate difficulty and adapts after each saved answer. If you open a solution before answering, that attempt earns no credit, so your mastery stays honest.

Start the Magnetism and Matter test

Chapters either side of Magnetism and Matter by weight

Thermal Properties of Matter Weight 2.4/100 Basic Maths and Vectors Weight 2.2/100 Mechanical Properties of Solids Weight 1.6/100 Thermodynamics Weight 0.9/100

Magnetism and Matter: NEET PYQs and weightage

Magnetism and Matter: formula sheet for NEET

Torque on a magnet in a field

Potential energy of a dipole

Work to rotate a magnet

Net force in a uniform field

Axial field of a short magnet

Equatorial field of a short magnet

Gauss's law for magnetism

Magnetisation

Field inside a long solenoid

Total field in a material

Susceptibility

Permeability links

Field with a core

Material classes

How does NEET ask Magnetism and Matter?

Which topics in Magnetism and Matter carry the most questions?

Why does Magnetism and Matter show "–" until you answer 3 questions?

What happens when you test Magnetism and Matter?

Chapters either side of Magnetism and Matter by weight