NEET PhysicsUpdated 19 Oct 2026

Electric Charges and Fields: NEET PYQs and weightage

Electric Charges and Fields carries 2.6 of 100 Physics marks in NEET by past-paper share: 20 of the 758 tagged NEET Physics PYQs in the ViJEEta bank (NEET 2013–2026). It ranks 21 of 30 Physics chapters.

Take the 25-question Electric Charges and Fields test Formula sheet ↓All NEET Physics chapters

2.6/100 Weight in Physics

Exam importance (3/5, by past-paper share)

20 NEET PYQs

379 Practice questions

366 With measured difficulty

How the weight is computed: this chapter's tagged NEET PYQs divided by all tagged NEET Physics PYQs in the bank (20 of 758), times 100, with repeated questions counted once. The bank does not store the year of each NEET question, so none is printed. Computed from the bank at build time. Updated 19 Oct 2026.

Electric Charges and Fields: formula sheet for NEET

16 formulas, each with when to use it. Copy it onto one page of your notebook: that page is this chapter's handbook.

Coulomb's law
$F = \frac{1}{4 π ε _{0}} \frac{q _{1} q _{2}}{r ^{2}} (along the line joining the charges)$
$k = \frac{1}{4 π ε _{0}} \approx 9 \times 1 0^{9} N m^{2} C^{- 2}$
$ε_{0} = 8.854 \times 1 0^{- 12} C^{2} N^{- 1} m^{- 2}$
Use it when: Two point charges (or spheres far apart) push or pull each other in vacuum.
Charge is quantised and conserved
$q = n e (n = 0, \pm 1, \pm 2, \dots)$
$e = 1.6 \times 1 0^{- 19} C$
The total charge of an isolated system never changes.
Use it when: You need the number of electrons added or removed, or charge is shared between touching bodies.
Field of a point charge
$E = \frac{F}{q _{0}} = \frac{1}{4 π ε _{0}} \frac{q}{r ^{2}} (outward for + q, inward for - q; unit N/C)$
Use it when: You need the force per unit positive charge at a distance $r$ from one charge.
Force on a charge in a field
$F = q E$
$a = \frac{q E}{m} (a negative charge is pushed against E)$
Use it when: A charged particle (electron, proton) moves or falls in a uniform field.
Superposition
$E = i \sum \frac{1}{4 π ε _{0}} \frac{q _{i}}{r _{i}^{2}} \overset{r}{^}_{i} (vector sum; force works the same way)$
Use it when: Several charges act at once; add them as vectors, never as plain numbers.
Field-line rules
Lines start on $+ q$ and end on $- q$ , never cross, never form closed loops; where they crowd, $E$ is strong.
Use it when: A question shows a field-line picture and asks for signs or where $E$ is strongest.
Dipole moment
$p = q \times 2 a (pointing from - q to + q; unit C m)$
Use it when: A pair $\pm q$ sits a distance $2 a$ apart.
Dipole field on the axis
$E = \frac{2 p}{4 π ε _{0} r ^{3}} (along p) (exact: \frac{2 p r}{4 π ε _{0} ( r ^{2} - a ^{2} ) ^{2}})$
Use it when: The point lies on the line through the two charges, $r$ from the centre.
Dipole field on the equatorial line
$E = \frac{p}{4 π ε _{0} r ^{3}} (opposite to p) (exact: \frac{p}{4 π ε _{0} ( r ^{2} + a ^{2} ) ^{3/2}})$
Use it when: The point lies on the perpendicular bisector of the dipole.
Torque on a dipole
$τ = p \times E$
$∣ τ ∣ = pE sin θ (largest (pE) at θ = 9 0^{\circ})$
$F_{net} = 0 (in a uniform field)$
Use it when: A dipole sits at angle $θ$ to a uniform field.
Potential energy of a dipole
$U = - p \cdot E = - pE cos θ$
Use it when: You need the potential energy of a dipole at angle $θ$ to a uniform field.
Electric flux
$Δ ϕ = E \cdot Δ S = E Δ S cos θ (θ = angle between E and the area vector Δ S (along the normal to the area); unit N m^{2} C^{- 1})$
Use it when: A field crosses a flat area that may be tilted.
Gauss's law
$ϕ_{closed surface} = \frac{q _{enclosed}}{ε _{0}} (zero if no charge is inside, whatever the shape or size of the surface)$
Use it when: You know the charge inside a closed surface (cube, sphere, box) and need the total flux, or the reverse.
Infinite line charge
$E = \frac{λ}{2 π ε _{0} r} (radial)$
Use it when: You have a long uniformly charged wire, $r$ = perpendicular distance from it.
Infinite plane sheet
$E = \frac{σ}{2 ε _{0}} (normal to the sheet, same at every distance)$
Use it when: You have a large uniformly charged thin sheet.
Thin spherical shell
$E = \frac{1}{4 π ε _{0}} \frac{q}{r ^{2}} (r \geq R; as if all charge sat at the centre)$
$E = 0 (r < R)$
Use it when: Charge is spread uniformly on a shell of radius $R$ .

Trap

Students write E = σ/ε₀ for a single charged sheet. A lone sheet gives σ/(2ε₀), because its flux leaves through both faces of the Gaussian box.

How does NEET ask Electric Charges and Fields?

8 real previous-year questions from this chapter, as printed in the paper, each with its worked solution. Answer the first one here with no sign-in.

Q1PhysicsNEET UG PYQApplications of Gauss's Law

Try right here · No sign-in

A spherical conductor of radius 10 cm has a charge of

3.2 \times 1 0^{- 7}

C distributed uniformly, what is the magnitude of electric field at a point 15 cm from the centre of the sphere ?

(\frac{1}{4 π \in _{0}} = 9 \times 10^{9} N m^{2} / C^{2})

Answer key (D) & worked solution

Correct answer: Option D

E = \frac{k Q}{r ^{2}} = \frac{9 \times 10 ^{9} \times 3.2 \times 10 ^{- 7}}{15 \times 15 \times 10 ^{- 4}}

E = \frac{3.2}{25} \times 1 0^{6} = 0.128 \times 1 0^{6}

E = 1.28 \times 1 0^{5} N / C

Q2PhysicsNEET UG PYQCoulomb's Law

Suppose the charge of a proton and an electron differ slightly. One of them is –e the other (e +

Δ e) .

If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then

Δ e

is of the order of [Given mass of hydrogen m

_{h}

= 1.67 × 10–27 kg]

1 0^{- 37} C

1 0^{- 47} C

1 0^{- 20} C

1 0^{- 23} C

Answer key (A) & worked solution

Correct answer: Option A

F_{e} = F_{g}

\frac{1}{4 π ε _{0}} \frac{Δ e ^{2}}{d ^{2}} = \frac{G m ^{2}}{d ^{2}}

9 \times 1 0^{9} (Δ e^{2}) = 6.67 \times 1 0^{- 11} \times 1.67 \times 1 0^{- 27} \times 1.67 \times 1 0^{- 27}

Δ e^{2} = \frac{6.67 \times 1.67 \times 1.67}{9} \times 1 0^{- 74}

Δ e = 1 0^{- 37}

Q3PhysicsNEET UG PYQElectric Dipole

A electric dipole is placed at an angle of

3 0^{\circ}

with an electric field of intensity

2 \times 1 0^{5} N C^{- 1}

. It experiences a torque equal to 4 Nm. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.

A6 mC

B4 mC

C2 mC

D8 mC

Answer key (C) & worked solution

Correct answer: Option C

τ

on a dipole

= p \times E

τ = pE sin θ

4 = q \times l \times E \times sin 3 0^{\circ}

4 = q \times 2 \times 1 0^{- 2} \times 2 \times 1 0^{5} \times \frac{1}{2}

q = 2 \times 1 0^{- 3}

q = 2 m C

Q4PhysicsNEET UG PYQElectric Field

An electron falls from rest through a vertical distance h in a uniform and vertically upward directed electric field E. The direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance h. The time of fall of the electron, in comparison to the time of fall of the proton is

A10 times greater

B5 times greater

CSmaller

DEqual

Answer key (C) & worked solution

Correct answer: Option C

h = \frac{1}{2} \frac{e E}{m} t^{2}

∴ t = \frac{2 hm}{e E}

∴ t \propto m

as ‘e’ is same for electron and proton. ∵ Electron has smaller mass so it will take smaller time.

Q5PhysicsNEET UG PYQApplications of Gauss's Law

A conducting sphere of radius R is given a charge Q. The electric potential and the electric field at the centre of the sphere respectively are

\frac{Q}{4 π ε _{0} R}

and

\frac{Q}{4 π ε _{0} R ^{2}}

BBoth are zero

Czero and

\frac{Q}{4 π ε _{0} R ^{2}}

\frac{Q}{4 π ε _{0} R}

and zero

Answer key (D) & worked solution

Correct answer: Option D

V_{C e n t er} = V_{S u r f a ce} = \frac{K Q}{R}

; E = 0 [ Inside the conductor]

Q6PhysicsNEET UG PYQElectric Dipole

An electric dipole is placed at an angle of 30

^{o}

with an electric field intensity 2×10

^{5}

N/C. It experiences a torque equal to 4 Nm. The charge on the dipole, if the dipole length is 2 cm is

A2 mC

B5 mC

C7 μC

D8 mC

Answer key (A) & worked solution

Correct answer: Option A

C = P E sin θ

C = q ℓ E sin θ

4 = q \times 2 \times 1 0^{- 2} \times 2 \times 1 0^{5} sin 3 0^{\circ}

\Rightarrow q = 2 m C

Q7PhysicsNEET UG PYQApplications of Gauss's Law

The electric field in a certain region is acting radially outward and is given by

E = A r

where r is distance from centre of sphere. A charge contained in a sphere of radius

α

centered at the origin of the field, will be given by:

ε_{0} A α^{3}

4 π ε_{0} A α^{2}

A ε_{0} α^{2}

4 π ε_{0} A α^{3}

Answer key (D) & worked solution

Correct answer: Option D

\oint E . d s = E 4 π α^{2} = A . α 4 π α^{2} = 4 π A α^{3}

\oint E . d s = \frac{Q _{e n}}{ε _{0}} ∴ Q_{e n} = 4 π ε_{0} A α^{3}

Q8PhysicsNEET UG PYQElectric Field

In a certain region of space with volume

0.2 m^{3},

the electric potential is found to be 5 V throughout. The magnitude of electric field in this region is :

A1 N/C

B5 N/C

CZero

D0.5 N/C

Answer key (C) & worked solution

Correct answer: Option C

Given V = constant=5 V

E = - \frac{d V}{d r}

\Rightarrow E = 0

Which topics in Electric Charges and Fields carry the most questions?

All 11 topics, by tagged PYQs, then practice questions. Counted from the bank. Updated 19 Oct 2026.

Topic	PYQs	Practice questions
Coulomb's Law	5	45
Applications of Gauss's Law	5	37
Electric Field	4	72
Electric Dipole	4	71
Gauss's Law	1	29
Electric Charges, Conductors, and Insulators	1	16
Force Between Multiple Charges	0	31
Electric Flux	0	28
Electric Field Lines	0	26
Basic Properties of Electric Charge	0	12
Continuous Charge Distribution	0	12

Why does Electric Charges and Fields show "–" until you answer 3 questions?

Unknown is not zero. Until you answer at least 3 graded questions in Electric Charges and Fields, ViJEEta shows – instead of a zero or a 50% default. Book exercises can raise chapter mastery up to 0.60, adaptive practice up to 0.75, and only a timed chapter test or mock can certify 0.80 and above.

How ViJEEta scores you

What happens when you test Electric Charges and Fields?

Every chapter test is 25 questions. It starts at moderate difficulty and adapts after each saved answer. If you open a solution before answering, that attempt earns no credit, so your mastery stays honest.

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Electric Charges and Fields: NEET PYQs and weightage

Electric Charges and Fields: formula sheet for NEET

Coulomb's law

Charge is quantised and conserved

Field of a point charge

Force on a charge in a field

Superposition

Field-line rules

Dipole moment

Dipole field on the axis

Dipole field on the equatorial line

Torque on a dipole

Potential energy of a dipole

Electric flux

Gauss's law

Infinite line charge

Infinite plane sheet

Thin spherical shell

How does NEET ask Electric Charges and Fields?

Which topics in Electric Charges and Fields carry the most questions?

Why does Electric Charges and Fields show "–" until you answer 3 questions?

What happens when you test Electric Charges and Fields?

Chapters either side of Electric Charges and Fields by weight