Updated 19 Oct 2026

JEE Main 2025, 22 Jan Shift 1 question paper with solutions

JEE Main 2025, 22 Jan Shift 1 was held on 22 January 2025. The bank holds 71 of its questions (Physics 25, Chemistry 21, Mathematics 25). A sample with answer keys and worked solutions is below, or sit the complete shift paper in the official NTA CBT interface (180 minutes, 300 marks, +4 / −1). Real PYQ papers are never filtered by your covered syllabus.

Sit this paper in the exam screen All JEE Main 2025 shifts Marks vs percentile table

2025 Exam session year

300 Maximum marks (+4 / −1)

180 min Official duration

71 Questions in bank for this shift

Try questions from JEE Main 2025, 22 Jan Shift 1

Q1PhysicsJEE Main 2025, 22 Jan Shift 1Dielectrics in capacitors

Try right here · No sign-in

A parallel-plate capacitor of capacitance 40μF is connected to a 100 V power supply. Now the intermediate space between the plates is filled with a dielectric material of dielectric constant K = 2. Due to the introduction of dielectric material, the extra charge and the change in the electrostatic energy in the capacitor, respectively, are -

Answer key (C) & worked solution

Correct answer: Option C

Δ q = (K C - C) V

= 40 \times 1 0^{- 6} \times 100

= 4000 \times 1 0^{- 3} = 4 m C

Δ U = \frac{1}{2} C^{'} V^{2} - \frac{1}{2} C V^{2} = \frac{1}{2} (K - 1) C V^{2}

= \frac{1}{2} C V^{2} (2 - 1)

= \frac{1}{2} C V^{2} = \frac{1}{2} \times 40 \times 1 0^{- 6} \times 10000

= 0.2 J

Q2PhysicsJEE Main 2025, 22 Jan Shift 1Real and ideal cell

Given below are two statements : Statement-I : The equivalent emf of two nonideal batteries connected in parallel is smaller than either f the two emfs. Statement-II : The equivalent internal resistance of two nonideal batteries connected in parallel is smaller than the internal resistance of either of the two batteries. In the light of the above statements, choose the correct answer from the options given below.

AStatement-I is true but Statement-II is false

BBoth Statement-I and Statement-II are false

CBoth Statement-I and Statement-II are true

DStatement-I is false but Statement-II is true

Answer key (D) & worked solution

Correct answer: Option D

ε_{e q} = \frac{ε _{1} r _{2} + ε _{2} r _{1}}{r _{1} + r _{2}}

Check for

r_{1} = r_{2} \Rightarrow ε_{e q} = \frac{ε _{1} + ε _{2}}{2}

So S1 is flase

S 2 : r_{e q} = \frac{r _{1} r _{2}}{r _{1} + r _{2}} < r_{1} or r_{2}

S2 is true.

Q3ChemistryJEE Main 2025, 22 Jan Shift 1Vitamins

Which of the following acids is a vitamin ?

AAdipic acid

BAspartic acid

CAscorbic acid

DSaccharic acid

Answer key (C) & worked solution

Correct answer: Option C

Vitamin-C is Ascorbic acid.

Q4ChemistryJEE Main 2025, 22 Jan Shift 1Nuclear Chemistry

Which of the following statement is not true for radioactive decay ?

AAmount of radioactive substance remained after three half lives is

\frac{1}{8}

th of original amount.

BDecay constant does not depend upon temperature.

CDecay constant increases with increase in temperature.

DHalf life is ln 2 times of

\frac{1}{rate constant}

Answer key (C) & worked solution

Correct answer: Option C

Decay constant is independent of temperature

Q5MathematicsJEE Main 2025, 22 Jan Shift 1Log & its basic properties

The product of all solutions of the equation

e^{5 (l o g_{e} x)^{2} + 3} = x^{8}

x > 0

, is:

e^{8/5}

e^{6/5}

e^{2}

e

Answer key (A) & worked solution

Correct answer: Option A

e^{5 (l o g_{e} x)^{2} + 3} = x^{8}

\Rightarrow ln e^{5 (ℓ n x)^{2} + 3} = ln x^{8}

\Rightarrow 5 (ln x)^{2} + 3 = 8 ln x

(ln x = t)

\Rightarrow 5 t^{2} - 8 t + 3 = 0

t_{1} + t_{2} = \frac{8}{5}

ln x_{1} x_{2} = \frac{8}{5}

x_{1} x_{2} = e^{8/5}

Q6MathematicsJEE Main 2025, 22 Jan Shift 1Standard Equations of a Circle

Let the parabola y = x

^{2}

+ px – 3, meet the coordinate axes at the points P, Q and R. If the circle C with centre at (–1, –1) passes through the points P, Q and R, then the area of

Δ

PQR is:

Answer key (B) & worked solution

Correct answer: Option B

y = x

^{2}

+ px – 3 Let P(

α

, 0), Q(

β

, 0), R(0, –3) Circle with centre (–1, –1) is (x + 1)

^{2}

+ (y + 1)

^{2}

= r

^{2}

Passes through (0, –3) 1

^{2}

+ (–2)

^{2}

= r

^{2}

] r

^{2}

= 5 (x + 1)

^{2}

+ (y + 1)

^{2}

= 5 Put y = 0 (x + 1)

^{2}

= 5 – 1 (x + 1)

^{2}

= 4 x + 1 = ±2 x = 1 or x = –3

∴

P(1, 0) and Q(–3,0) Area of

\Delta PQR = \frac{1}{2}\left| {\begin{array}{*{20}{c}} 1&0&1 \\ { - 3}&0&1 \\ 0&{ - 3}&1 \end{array}} \right| = 6